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Question

Physics Question on Friction

A body of mass MM is kept on a rough horizontal surface [friction coefficient =u=u). A person is trying to pull the body by applying a horizontal force FF but the body is not moving then

A

F=MgF=Mg

B

F=μMgF=\mu Mg

C

MgFMg1+μ2Mg\le F\le Mg\sqrt{1+\mu ^{2}}

D

MgFMg1+μ2Mg\ge F\ge Mg\sqrt{1+\mu ^{2}}

Answer

MgFMg1+μ2Mg\le F\le Mg\sqrt{1+\mu ^{2}}

Explanation

Solution

Maximum force applied F=f2+R2F=\sqrt{f^{2}+R^{2}}, where f=f = force of friction Since, f=μRf=\mu R Then, f=μ2R2+R2=Rμ2+1f=\sqrt{\mu^{2} R^{2}+R^{2}}=R \sqrt{\mu^{2}+1} Now, if μ=0,F=Rs\mu=0, F=R s which is minimum force R=mg\because R=m g MgFMgμ2+1\therefore M g \leq F \leq M g \sqrt{\mu^{2}+1}