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Question: A body of mass 8kg is moved by a force \(x = 2 m\) and the final position is \(x = 10\)m. The initia...

A body of mass 8kg is moved by a force x=2mx = 2 m and the final position is x=10x = 10m. The initial speed is The final speed is

A

6 m/s

B

12 m/s

C

18 m/s

D

14 m/s

Answer

6 m/s

Explanation

Solution

Increment in kinetic energy = work done

12m(v2u2)=x1x2F.dx=210(3x)dx\frac { 1 } { 2 } m \left( v ^ { 2 } - u ^ { 2 } \right) = \int _ { x _ { 1 } } ^ { x _ { 2 } } F . d x = \int _ { 2 } ^ { 10 } ( 3 x ) d x

12mv2=32[x2]210=32[1004]\frac { 1 } { 2 } m v ^ { 2 } = \frac { 3 } { 2 } \left[ x ^ { 2 } \right] _ { 2 } ^ { 10 } = \frac { 3 } { 2 } [ 100 - 4 ]

12×8×v2=32×96\frac { 1 } { 2 } \times 8 \times v ^ { 2 } = \frac { 3 } { 2 } \times 96