Question
Question: A body of mass \(8\,kg\) is hanging from another body of mass \(12\,kg\). The combination is being p...
A body of mass 8kg is hanging from another body of mass 12kg. The combination is being pulled up by a string with an acceleration of 2.2m/sec2. The tension T1 will be ?
Solution
In order to answer this question let us first go through pulley. Pulleys are wheel-and-rope devices that are used to carry large items to great heights. They can alter the direction of applied force and even reduce the amount of force required to lift a weight. Pulleys are sometimes used in buildings.
Complete step by step answer:
Tension is described as a pair of opposing forces acting at each end of the elements in question. A rope's tension force is felt by any segment of the rope in both directions, with the exception of the endpoints. The endpoints are subjected to friction on one side and force from the attached weight on the other. In certain cases, the stress varies across the string.
T=mg
where, T is the tension, m= mass and g= gravitational force.
When two bodies move upwards with acceleration, gravity exerts a downward force i.e. (m1+m2)g
According to Newton’s 2nd law
T1=(m1+m2)g=(m1+m2)a ⇒T1=(m1+m2)×(a+g) ⇒T1=(12+8×)(2.2+9.8) ⇒T1=(20)×(12) ∴T1=240N
Similarly,
T2=m2(a+g) ⇒T2=8×(2.2+9.8) ⇒T2=8×12 ∴T2=96N
Hence, according to the question the tension T1 will be 240N.
Note: Now, you might wonder if the tension in a rope is always the same. If the rope's force isn't used to accelerate anything else, including itself, the tension in the rope remains constant. As a result, if it is kept taut between two points and has zero mass, the stress would be considered constant throughout.