Question

A body of mass 5kg initially at rest explodes into 3 fragments with mass ratio 3 : 1 : 1. Two of fragments each of mass m are found to move with a speed 60m/s in mutually perpendicular directions. The velocity of third fragment is

• A. 60√2 m/s
• B. 20√3 m/s
• C. 10√2 m/s
• D. 20√2 m/

Answer 1

Answer: (D)

20√2 m/

Answer 2

3mv = $\sqrt{(m \times 60)^{2} + (m \times 60)^{2}}$ = m 60√2

v = 20√2 m/s