Question

A body of mass $50\, kg$. is suspended using a spring balance inside a lift at rest. If the lift starts falling freely, the reading of the spring balance is

• A. #ERROR!
• B.

  50 kg

• C. < 50 kg
• D. 0

Answer 1

Answer: (D)

0

Answer 2

Given,
Mass of the body, $m=50\, kg$
When lift is moving down.
Scale reading $=\frac{m(g-a)}{g}$
If lift starts falling freely. then $a=g$
Now, scale reading $=\frac{m(g-g)}{q}$
$=0$