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Question: A body of mass 50 kg is projected vertically upwards with velocity of 100 m/sec. 5 seconds after thi...

A body of mass 50 kg is projected vertically upwards with velocity of 100 m/sec. 5 seconds after this body breaks into 20 kg and 30 kg. If 20 kg piece travels upwards with 150 m/sec, then the velocity of other block will be

A

15 m/sec downwards

B

15 m/sec upwards

C

51 m/sec downwards

D

51 m/sec upwards

Answer

15 m/sec downwards

Explanation

Solution

Velocity of 50 kg. mass after 5 sec of projection v=ugtv = u - g t =1009.8×5=51 m/s= 100 - 9.8 \times 5 = 51 \mathrm {~m} / \mathrm { s }

At this instant momentum of body is in upward direction

Pinitial =50×51=2550 kgm/sP _ { \text {initial } } = 50 \times 51 = 2550 \mathrm {~kg} - \mathrm { m } / \mathrm { s }

After breaking 20 kg piece travels upwards with 150 m/s let the speed of 30 kg mass is V

Pfinal =20×150+30×VP _ { \text {final } } = 20 \times 150 + 30 \times V

By the law of conservation of momentum

2550=20×150+30×VV=15 m/s2550 = 20 \times 150 + 30 \times V \Rightarrow V = - 15 \mathrm {~m} / \mathrm { s }

i.e. it moves in downward direction.