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Question

Physics Question on work, energy and power

A body of mass 5kg5\, kg is moving with a momentum of 10kgm/s10\,kg\,m/s . A force of 0.2N0.2\,N acts on it in the direction of motion of the body for 10s10\, s. The increase in its kinetic energy is

A

2.8J2.8\,\,J

B

3.2J3.2\,\,J

C

3.8J3.8\,\,J

D

4.4J4.4\,\,J

Answer

4.4J4.4\,\,J

Explanation

Solution

Change in momentum == force ×\times time p2p1=0.2×10=2kgm/s\Rightarrow p_{2}-p_{1}=0.2 \times 10=2\, kg\, m / s p2=p1+2=10+2=12kgm/s\Rightarrow p_{2}=p_{1}+2=10+2=12\, kg\, m / s Increase in KE=12m(p22p12)KE =\frac{1}{2 m}\left(p_{2}^{2}-p_{1}^{2}\right) =12×5[(12)2(10)2]=\frac{1}{2 \times 5}\left[(12)^{2}-(10)^{2}\right] =110×(144100)=\frac{1}{10} \times(144-100) =4.4J=4.4\, J