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Question

Physics Question on System of Particles & Rotational Motion

A body of mass 5kg5 \,kg acquires an angular acceleration of 10rads210\, rad\, s^{-2} by an applied torque of 2Nm2 \,N m . Find its radius of gyration.

A

2.5m2.5\,m

B

2.5m\sqrt{2.5} \,m

C

0.2m\sqrt{0.2}\, m

D

0.2m0.2\,m

Answer

0.2m0.2\,m

Explanation

Solution

m=5Kgm=5\,Kg,
α=10\alpha=10 rad s2s^{-2},
τ=2Nm\tau=2\,N\,m
Torque, τ=Iα=mk2α(I=mk2)\tau=I \alpha=mk^{2}\alpha \left(\because I=mk^{2}\right)
where kk is the radius of gyration
2=5×k2×10\therefore 2=5\times k^{2}\times10
or k2=0.04k^{2}=0.04 or k=0.2mk=0.2\,m