Question

A body of mass 5 gm is executing S.H.M about a point with amplitude 10 cm. Its maximum velocity is 100 cm/s. Its velocity will be 50 cm/s at a distance –

• A. 5
• B. $5\sqrt{2}$
• C. $5\sqrt{3}$
• D. $10\sqrt{2}$

Answer 1

Answer: (C)

$5\sqrt{3}$

Answer 2

Q v = ω$\sqrt{A^{2}–x^{2}}$

V_max = Aω ⇒ 100 = 10 × ω

ω = 10 rad/s

So v = 50 = $10\sqrt{10^{2}–x^{2}}$

⇒ x = $5\sqrt{3}$cm