Question

A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec, at a distance

• A. 5
• B. $5\sqrt{2}$
• C. $5\sqrt{3}$
• D. $10\sqrt{2}$

Answer 1

Answer: (C)

$5\sqrt{3}$

Answer 2

${v\sec}_{\max}$ and $a = 10cm$ so

$\omega = 10rad/sec.$

∴ $v = \omega\sqrt{a^{2} - y^{2}}$ ⇒ 50 = $10\sqrt{10^{2} - y^{2}}$⇒ $y = 5\sqrt{3}$