Question

A body of mass $200\, g$ is tied to a spring of spring constant $12.5\, N / m$, while the other end of spring is fixed at point $O$. If the body moves about $O$ in a circular path on a smooth horizontal surface with constant angular speed $5\, rad / s$. Then the ratio of extension in the spring to its natural length will be :

• A. $1: 1$
• B. $2: 3$
• C. $2:5$
• D. $1: 2$

Answer 1

Answer: (B)

$2: 3$

Answer 2

The correct answer is (B) : 2 : 3

kx=m(L0​+x)ω2
⇒12.5x=51​(L0​+x)25⇒1.5x=L0​
⇒L0​x​=32​