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Question

Physics Question on Oscillations

A body of mass 20g20\, g connected to spring of constant kk executes simple harmonic motion with a frequency of (5π)Hz\bigg(\frac{5}{\pi}\bigg)Hz. The value of spring constant is

A

4 N m1^{-1}

B

3 N m1^{-1}

C

2 N m1^{-1}

D

5 N m1^{-1}

Answer

2 N m1^{-1}

Explanation

Solution

Mass (m) = 20g = 0.02 kg
Frequency (f) =5πHz\frac{5}{\pi} Hz
Time period of a loaded spring
T=2πmk\, \, \, \, \, \, \, \, \, \, \, T=2\pi \sqrt{\frac{m}{k}}
Frequency (f) = 12πkm\frac{1}{2\pi}\sqrt{\frac{k}{m}}
5π=12πk0.02\, \, \, \, \, \, \, \, \, \frac{5}{\pi}=\frac{1}{2\pi}\sqrt{\frac{k}{0.02}}
or 10=k0.02or100=k0.02\, \, \, \, \, \, \, \, \, \, \, \, 10=\sqrt{\frac{k}{0.02}} \, or \, 100 =\frac{k}{0.02}
k=2Nm1\therefore \, \, \, \, \, \, \, \, \, \, \, \, k=2 Nm^{-1}