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Question: A body of mass 20 g connected to a spring of spring constant k, executes simple harmonic motion with...

A body of mass 20 g connected to a spring of spring constant k, executes simple harmonic motion with a frequency of (5/π\pi) Hz. The value fo spring constant is

A

4 N m–1

B

3 N m–1

C

2 N m–1

D

5 N m–1

Answer

2 N m–1

Explanation

Solution

Here, m=20 g=20×103 kg,v=5πHz\mathrm { m } = 20 \mathrm {~g} = 20 \times 10 ^ { - 3 } \mathrm {~kg} , \mathrm { v } = \frac { 5 } { \pi } \mathrm { Hz }

As v=12πkmv = \frac { 1 } { 2 \pi } \sqrt { \frac { k } { m } }