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Question

Physics Question on work, energy and power

A body of mass 2kg2\, kg makes an elastic collision with another body at rest and continues to move in the original direction with one-fourth its original speed. The mass of the second body which collides with the first body is

A

2 kg

B

1.2 kg

C

3 kg

D

1.5 kg

Answer

1.2 kg

Explanation

Solution

Conservation of linear momentum gives m1u1+m2u2=m1v1+m2v2m_{1} u_{1} +m_{2} u_{2} =m_{1} v_{1}+m_{2} v_{2} m2v2=3u2\Rightarrow m_{2} v_{2} =\frac{3 u}{2} Conservation of kinetic energy gives 12m1u12+12m2u22\frac{1}{2} m_{1} u_{1}^{2}+\frac{1}{2} m_{2} u_{2}^{2} =12m1v12+12m2v22=\frac{1}{2} m_{1} v_{1}^{2}+\frac{1}{2} m_{2} v_{2}^{2} m2v22=15u28\Rightarrow m_{2} v_{2}^{2}=\frac{15 u^{2}}{8} Hence, on solving Eqs. (i) and (ii), we get m2=1.2kgm_{2}=1.2\, kg