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Question: A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The...

A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is

(J=4.2( J = 4.2 joule / cal and g=9.8m/s2)\left. g = 9.8 m / s ^ { 2 } \right)

A

9.33 cal

B

10.21 cal

C

12.67 cal

D

13.34 cal

Answer

9.33 cal

Explanation

Solution

Work done = Force × Displacement

=μmg×(v×t)= \mu m g \times ( v \times t )

W=(0.2)×2×9.8×2×5W = ( 0.2 ) \times 2 \times 9.8 \times 2 \times 5 joule

Heat generated Q =WJ= \frac { W } { J } =0.2×2×9.8×2×54.2= \frac { 0.2 \times 2 \times 9.8 \times 2 \times 5 } { 4.2 }

=9.33= 9.33 cal