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Question

Physics Question on work, energy and power

A body of mass 2 kg, initially at rest, is moved by 3 m along the horizontal by a force of 10 N acting at an angle of 60?60^? with the horizontal. The kinetic energy gained by the body is

A

15J15\,J

B

20J20\,J

C

25J25\,J

D

30J30\,J

Answer

15J15\,J

Explanation

Solution

Component of force along the direction of displacement =Fcos?=10?cos60?=5N= F \,cos? = 10 ? cos60^? = 5 \,N Therefore, acceleration is a=5N2kg=2.5ms2a=\frac{5\,N}{2\,kg}=2.5\,m\,s^{-2} As υ2u2=2as\upsilon^{2}-u^{2}=2as or υ2=2as(u=0)\upsilon^{2}=2as\,\left(\because u=0\right) K.E=12mυ2=mas=2×2.5×3=15J\therefore K.E=\frac{1}{2}m\upsilon^{2}=mas=2\times2.5\times3=15\,J