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Question

Question: A body of mass 2 kg collides with a wall with speed 100 m/s and rebounds with same speed. If the tim...

A body of mass 2 kg collides with a wall with speed 100 m/s and rebounds with same speed. If the time of contact was 1/50 second, the force exerted on the wall is

A

8 N

B

2×104N2 \times 10^{4}N

C

4 N

D

104N10^{4}N

Answer

2×104N2 \times 10^{4}N

Explanation

Solution

F=dpdt=mdvdt=m×2v1/50F = \frac { d p } { d t } = m \frac { d v } { d t } = \frac { m \times 2 v } { 1 / 50 } = 2×2×1001/50=2×104 N\frac { 2 \times 2 \times 100 } { 1 / 50 } = 2 \times 10 ^ { 4 } \mathrm {~N}