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Question

Question: A body of mass \(1kg\) is executing simple harmonic motion. Its displacement \(y(cm)\) at t seconds ...

A body of mass 1kg1kg is executing simple harmonic motion. Its displacement y(cm)y(cm) at t seconds is given by

y=6sin(100t+π/4)y = 6\sin(100t + \pi ⥂ / ⥂ 4). Its maximum kinetic energy is

A

6 J

B

18 J

C

24 J

D

36 J

Answer

18 J

Explanation

Solution

So a=6cm,6muω=100rad/seca = 6cm,\mspace{6mu}\omega = 100rad/\sec

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