Question

A body of mass 1kg crosses a point O with a velocity 60 ms^–1. A force of 10N directed towards O begins to act on it. It will again cross O in –

• A. 24 s
• B. 12 s
• C. 6s
• D. Will never return to O

Answer 1

Answer: (B)

12 s

Answer 2

t = $\frac { | \vec { v } - \vec { u } | } { | \overrightarrow { \mathrm { a } } | }$ = $\frac { | - 60 - 60 | } { ( 10 / 1 ) }$ = 12 sec.