Question

A body of mass 100g is tied to one end of spring of constant 20 N/m. The distance between pole of mirror and mean position of the body is 20cm. The focal length of convex mirror is 10cm. One of the amplitudes of vibration of the image is –

• A. 10 cm
• B. 50 cm
• C. 0.67 cm
• D. 0.33 cm

Answer 1

Answer: (C)

0.67 cm

Answer 2

Kx = mg

x = $\frac { \mathrm { mg } } { \mathrm { K } } = \frac { 0.1 \times 10 } { 20 } = \frac { 1 } { 20 }$= 5 cm,

Apply