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Question: A body of mass 100 g is sliding from an inclined plane of inclination 30°. What is the frictional fo...

A body of mass 100 g is sliding from an inclined plane of inclination 30°. What is the frictional force experienced if μ=1.7\mu = 1.7

A

1.7×2×13N1.7 \times \sqrt { 2 } \times \frac { 1 } { \sqrt { 3 } } N

B

1.7×3×12N1.7 \times \sqrt { 3 } \times \frac { 1 } { 2 } N

C

1.7×3N1.7 \times \sqrt { 3 } N

D

1.7×2×13N1.7 \times \sqrt { 2 } \times \frac { 1 } { 3 } N

Answer

1.7×3×12N1.7 \times \sqrt { 3 } \times \frac { 1 } { 2 } N

Explanation

Solution

Fk=μkR=μkmgcosθF _ { k } = \mu _ { k } R = \mu _ { k } m g \cos \theta

Fk=1.7×0.1×10×cos30F _ { k } = 1.7 \times 0.1 \times 10 \times \cos 30 ^ { \circ } =1.7×32 N= 1.7 \times \frac { \sqrt { 3 } } { 2 } \mathrm {~N}