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Question

Physics Question on Kinetic Energy

A body of mass 10kg10 kg is moving with an initial speed of 20m/s20 m / s The body stops after 5s5 s due to friction between body and the floor The value of the coefficient of friction is: (Take acceleration due to gravity g=10ms2g =10 ms ^{-2} )

A

0.20.2

B

0.40.4

C

0.50.5

D

0.3

Answer

0.40.4

Explanation

Solution

a=μga=-\mu g
v=u+at\because v=u+at
0=20+(μ×10)×50=20+(\mu\times10)\times5
50μ=2050\mu=20
μ=25\mu=\frac{2}{5}
=0.4
Therefore , the value of coefficient of friction is 0.4
So , the correct option is (B) : 0.4