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Question: A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 ...

A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 sec on it, it moves with a velocity 2 m/sec in the opposite direction. The acceleration produced in it is

A

3m/s23m/s^{2}

B

−3m/s2- 3m/s^{2}

C

0.3m/s20.3m/s^{2}

D

−0.3m/s2- 0.3m/s^{2}

Answer

−3m/s2- 3m/s^{2}

Explanation

Solution

Let particle moves towards east and by the application of constant force it moves towards west

υ→1=+10m/s{\overrightarrow{\upsilon}}_{1} = + 10m/s and υ→2=−2m/s{\overrightarrow{\upsilon}}_{2} = - 2m/s.

Acceleration =Change in velocityTime=υ2→−υ1→t= \frac{\text{Change in velocity}}{\text{Time}} = \frac{\overset{\rightarrow}{\upsilon_{2}} - \overset{\rightarrow}{\upsilon_{1}}}{t}

⇒ a=(−2)−(10)4a = \frac{( - 2) - (10)}{4} =−124=−3m/s2= \frac{- 12}{4} = - 3m/s^{2}