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Question: A body of mass \(10\,kg\) is moving on an inclined plane of inclination \(30^\circ \) with an accele...

A body of mass 10kg10\,kg is moving on an inclined plane of inclination 3030^\circ with an acceleration 2msec22\,m{\sec ^{ - 2}} the body starts from rest. Find the work done by force of gravity in 2s2\,s
A. 10J10J
B. 00
C. 198J198J
D. 196J196J

Explanation

Solution

In order to solve this question we need to understand work done and work energy theorem. Work is defined as force needed to move an object to some displacement and it is mathematically defined as W=F.rW = F.r . Also the work energy theorem is defined as work done by force is stored in the body in the form of energy. Work can be positive, negative or zero depending on the angle between displacement and force applied.

Complete step by step answer:
Mass of body, m=10kgm = 10kg and angle of inclination is θ=30\theta = 30^\circ . Since the body is moving with constant acceleration, we can use the equation of motion to calculate the distance it moves to move up an inclined plane.

Let the distance moved be “r” by body with acceleration, a=2msec2a = 2\,m{\sec ^{ - 2}} and in time, t=2sect = 2\sec is given by
r=ut+12at2r = ut + \dfrac{1}{2}a{t^2}
Since the body starts from rest, u=0msec1u = 0m{\sec ^{ - 1}}.
Putting values we get,
r=12(2)×(4)r = \dfrac{1}{2}(2) \times (4)
r=4m\Rightarrow r = 4\,m
Now the force due to gravity is, F=mgF = mg.
Here “g” is acceleration due to gravity, g=9.8msec2g = 9.8\,m\,{\sec ^{ - 2}}

Putting values we get,
F=(10)(9.8)NF = (10)(9.8)N
F=98N\Rightarrow F = 98N
Also the angle between displacement and force is,
ϕ=90+30\phi = 90^\circ + 30^\circ
ϕ=120\Rightarrow \phi = 120^\circ
So using work formula we get, W=F.rW = F.r
W=FrcosϕW = Fr\cos \phi
Putting values we get,
W=(98)(4)cos(120)W = (98)(4)\cos (120)
W=392×(12)\Rightarrow W = 392 \times ( - \dfrac{1}{2})
W=196J\therefore W = - 196J
Here the work done is negative which shows that the work is done against gravity.

So the correct option is D.

Note: It should be remembered that here we can use the equation of motion since the acceleration is constant and uniform but if acceleration is non uniform then we have to use integration techniques or continuous distribution techniques to find the distance up to which the body moves. Also in the center of mass frame if the inclination is not fixed then it must move backward in order to conserve momentum.