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Question: A body of mass 10 kg is lying on a rough plane inclined at an angle of 30<sup>o</sup> to the horizon...

A body of mass 10 kg is lying on a rough plane inclined at an angle of 30o to the horizontal and the coefficient of friction is 0.5. The minimum force required to pull the body up the plane is

A

914 N

B

91.4 N

C

9.14 N

D

0.914

Answer

91.4 N

Explanation

Solution

F=mg(sinθ+μcosθ)F = m g ( \sin \theta + \mu \cos \theta )

=10×9.8(sin30+0.5cos30)=91.4 N= 10 \times 9.8 \left( \sin 30 ^ { \circ } + 0.5 \cos 30 ^ { \circ } \right) = 91.4 \mathrm {~N} .