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Question

Physics Question on work, energy and power

A body of mass 10 kg initially at rest acquires velocity 10ms110 ms^{-1}. What is the work done

A

-500 J

B

500 J

C

50 J

D

-50 J

Answer

500 J

Explanation

Solution

By work-energy theorem
W=ΔK=12×10×(10)20W =\Delta K=\frac{1}{2}\times 10\times (10)^2 -0
=500 J