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Question

Physics Question on work, energy and power

A body of mass 1kg1 \,kg begins to move under the action of a time dependent force F=(i^+3t2j^)N\vec{F}=\left(\hat{i}+3 t^2 \hat{j}\right) N, where i^\hat{i} and j^\hat{j} are the unit vectors along xx and yy axis The power developed by above force, at the time t=2st=2 s\,, will be _________W

Answer

The correct answer is 100.
F=ti^+3t2j^​
dtmdv​=ti^+3t2j^​
m=1kg,0∫v​dv=0∫t​tdti^+0∫t​3t2dtj^​
v=2t2​i^+t3j^​
Power =F⋅V=2t3​+3t5
At t=2, power =28​+3×32
=100