Question

A body of mass 0.01 kg execute S.H.M about x = 0, under the influence of a force shown below the period of the S.H.M. is –

• A. 1.05 s
• B. 0.52 s
• C. 0.25 s
• D. 0.30 s

Answer 1

Answer: (D)

0.30 s

Answer 2

From graph Slope k = $\frac { 80 } { 20 }$= 4

k = mw² = 4

w² = $\frac { 4 } { 0.01 }$= 400

w = 20 rad/s

So T = $\frac { 2 \pi } { 2 }$= 0.3 sec.