Question

A body of mass $0.5 \,kg$ is projected under gravity with a speed of $98 \,m/s$ at an angle of $60^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is

• A. 24.5 N-s
• B. 49.0 N-s
• C. 98.0 N-s
• D. 50.0 N-s

Answer 1

Answer: (A)

24.5 N-s

Answer 2

Initial momentum $=mu=0$ Final momentum $= m$ (Horizontal component of velocity) $=m(v\,\,\cos \theta ) =0.5\times 98\times \cos \,\,60$ $=24.5N\text{-s}$ $\therefore$ Change in momentum $=24.5-0$ $=24.5N\text{-s}$