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Question

Physics Question on Kinetic Energy

A body of mass 0.5kg0.5\, kg is projected under gravity with a speed of 98m/s98\, m / s at an angle of 6060^{\circ} with the horizontal. The change in momentum (in magnitude) of the body is

A

24.5 N-s

B

49.0 N-s

C

98.0 N-s

D

50.0 N-s

Answer

49.0 N-s

Explanation

Solution

Initially body is at rest. Initial momentum p1=m×0p_{1}=m \times 0 p1=0p_{1}= 0 Final momentum p2=mvp_{2}=m v =0.5×98=49N=0.5 \times 98=49\, N Change in momentum =p2p1=p_{2}-p_{1} =490=409N5=49-0=409\, N -5