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Question

Physics Question on laws of motion

A body of mass 0.1kg0.1\, kg attains a velocity of 10ms1 10\,ms^{-1} in 0.1s.0.1 \,s. The force acting on the body is :

A

10 N

B

0.01 N

C

0.1 N

D

100 N

Answer

10 N

Explanation

Solution

F=ma=m×ΔvΔtF=ma=m\times \frac{\Delta v}{\Delta t} =0.1×100.1=10N=0.1\times \frac{10}{0.1}=10\,\,N