Question

A body of 5 kg weight kept on a rough inclined plane of angle 30^o starts sliding with a constant velocity. Then the coefficient of friction is (assume g = 10 m/s²)

• A. $1/\sqrt{3}$
• B. $2/\sqrt{3}$
• C. $\sqrt{3}$
• D. $2\sqrt{3}$

Answer 1

Answer: (A)

$1/\sqrt{3}$

Answer 2

Here the given angle is called the angle of repose

So, $\mu = \tan 30^{o} = \frac{1}{\sqrt{3}}$