Question
Physics Question on laws of motion
A body moving with uniform acceleration describes 12 m in the third second of its motion and 20 m in the 5th second. Find the velocity after 10 th second.
A
40 m/s
B
42 m/s
C
52 m/s
D
4m/s
Answer
42 m/s
Explanation
Solution
Sn=u+2a(2n−1) 12=u+2a(2×3−1) ..(i) and 20=u+2a(2×5−1) ..(ii) Subtract E (i) from E (ii) 8=2a(9−5)=2a ⇒ a=4m/s2 From E (i) 12=u+24×5 u=2m/s Velocity v=u+at=2+4×10 =42m/s