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Question

Physics Question on laws of motion

A body moving with uniform acceleration describes 12 m in the third second of its motion and 20 m in the 5th second. Find the velocity after 10 th second.

A

40 m/s

B

42 m/s

C

52 m/s

D

4m/s

Answer

42 m/s

Explanation

Solution

Sn=u+a2(2n1){{S}_{n}}=u+\frac{a}{2}(2n-1) 12=u+a2(2×31)12=u+\frac{a}{2}(2\times 3-1) ..(i) and 20=u+a2(2×51)20=u+\frac{a}{2}(2\times 5-1) ..(ii) Subtract E (i) from E (ii) 8=a2(95)=2a8=\frac{a}{2}(9-5)=2a \Rightarrow a=4m/s2a=4m/{{s}^{2}} From E (i) 12=u+42×512=u+\frac{4}{2}\times 5 u=2m/su=2\,m/s Velocity v=u+at=2+4×10v=u+at=2+4\times 10 =42m/s=42\,m/s