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Question: A body moving along a straight line travels one third of the total distance with a speed of 3.0 m s<...

A body moving along a straight line travels one third of the total distance with a speed of 3.0 m s-1. The remaining distance is covered with a speed of 4.0 m s-1 for half the time and 5.0 m s-1 for the other half of the time. The average speed during the motion is

A

4.0 m s-1

B

6.0 m s-1

C

3.8 m s-1

D

2.4 m s-1

Answer

3.8 m s-1

Explanation

Solution

Let s be the total distances travelled by the body. Let t1t_{1}be the time taken to cover the first one their of the distance. Then

t1=S/33=S9t_{1} = \frac{S/3}{3} = \frac{S}{9}

Let t2t_{2}be the time taken for each of the remaining two journeys. Then

SS3=4t2+5t2S - \frac{S}{3} = 4t_{2} + 5t_{2}or2s3=9t2\frac{2s}{3} = 9t_{2}or t2=2S27t_{2} = \frac{2S}{27}

Average speed = Total dis tan ce traveled  Total time taken =St1+2t2= \frac { \text { Total dis tan ce traveled } } { \text { Total time taken } } = \frac { \mathrm { S } } { \mathrm { t } _ { 1 } + 2 \mathrm { t } _ { 2 } } SS9+2(2S27)=3.8ms1\frac{S}{\frac{S}{9} + 2\left( \frac{2S}{27} \right)} = 3.8ms^{- 1}