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Question

Physics Question on Motion in a plane

A body moving along a circular path of radius RR with velocity vv, has centripetal acceleration a. If its velocity is made equal to 2v2v, then its centripetal acceleration is

A

4a4\,a

B

2a2\,a

C

a4\frac{a}{4}

D

a2\frac{a}{2}

Answer

4a4\,a

Explanation

Solution

The centripetal acceleration a=v2Ra=\frac{v^{2}}{R}
or av2a \propto v^{2}
or a1a2=v12v22\frac{a_{1}}{a_{2}}=\frac{v_{1}^{2}}{v_{2}^{2}}
=aa2=v2(2v)2=14=\frac{a}{a_{2}}=\frac{v^{2}}{(2 v)^{2}}=\frac{1}{4}
or a2=4aa_{2}=4\, a