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Question

Physics Question on Motion in a plane

A body moves 6m6\,m north, 8m8\,m east and 10m10\,m vertically upwards, the resultant displacement from its initial position is

A

102m10\sqrt{2}\,m

B

10m10\,m

C

102m\frac{10}{\sqrt{2}}\,m

D

20m20\,m

Answer

102m10\sqrt{2}\,m

Explanation

Solution

The situation is as shown in the figure OC=OA2+AB2+BC2OC=\sqrt{OA^{2}+AB^{2}+BC^{2}} =62+82+102=\sqrt{6^{2}+8^{2}+10^{2}} =102m=10\sqrt{2}\,m