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Question: A body is vibrating in simple harmonic motion with an amplitude of 0.06 m and frequency of 15 Hz. Th...

A body is vibrating in simple harmonic motion with an amplitude of 0.06 m and frequency of 15 Hz. The velocity and acceleration of body is

A

5.65m/s5.65m ⥂ / ⥂ s and 5.32×102m/s25.32 \times 10^{2}m ⥂ / ⥂ s^{2}

B

6.82m/s6.82m ⥂ / ⥂ s and 7.62×102m/s27.62 \times 10^{2}m ⥂ / ⥂ s^{2}

C

8.91m/s8.91m ⥂ / ⥂ s and 8.21×102m/s28.21 \times 10^{2}m ⥂ / ⥂ s^{2}

D

9.82m/s9.82m ⥂ / ⥂ s and 9.03×102m/s29.03 \times 10^{2}m ⥂ / ⥂ s^{2}

Answer

5.65m/s5.65m ⥂ / ⥂ s and 5.32×102m/s25.32 \times 10^{2}m ⥂ / ⥂ s^{2}

Explanation

Solution

Velocityv=aω=a×2π6munv = a\omega = a \times 2\pi\mspace{6mu} n

=0.06×2π×15=5.656mum/s= 0.06 \times 2\pi \times 15 = 5.65\mspace{6mu} m/s

Acceleration A=ω2a=4π2n2a=5.32×102m/s2A = \omega^{2}a = 4\pi^{2}n^{2}a = 5.32 \times 10^{2}m/s^{2}