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Question

Physics Question on Motion in a plane

A body is thrown with a velocity of 9.8 m/s making an angle of 3030{}^\circ with the horizontal. It will hit the ground after a time:

A

1.5 s

B

1 s

C

3s

D

2s

Answer

1 s

Explanation

Solution

The time of flight =2usinθg=\frac{2u\sin \theta }{g} =2×9.8×sin309.8=1s=\frac{2\times 9.8\times \sin 30{}^\circ }{9.8}=1\,s