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Question: A body is thrown up in a lift with a velocity 5 m/s relative to the lift and the time of flight is f...

A body is thrown up in a lift with a velocity 5 m/s relative to the lift and the time of flight is found to be 0.8 sec. The acceleration with which the lift is moving up will be : (g = 10 m/s2)

A

1.5 m/s2

B

2 m/s2

C

2.5 m/s2

D

3 m/s2

Answer

2.5 m/s2

Explanation

Solution

 Acceleration of body w. r. t. lift = g +a

 Time of flight of body, t = 2ug+a\frac{2u}{g + a}

 a = 2u−gtt\frac{2u - gt}{t} = (2×5)−(10×0.8)0.8\frac{(2 \times 5) - (10 \times 0.8)}{0.8} = 2.5 m/s2