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Question

Question: A body is thrown horizontally with velocity \(\sqrt{2gh}\) from the top of a tower of height h. It s...

A body is thrown horizontally with velocity 2gh\sqrt{2gh} from the top of a tower of height h. It strikes the level ground through the foot of tower at a distance x from the tower. The value of x is

A

h

B

h2\frac{h}{2}

C

2 h

D

2h3\frac{2h}{3}

Answer

2 h

Explanation

Solution

x=u×2hg=2gh×2hgx = u \times \sqrt{\frac{2h}{g}} = \sqrt{2gh} \times \sqrt{\frac{2h}{g}}

x=2hx = 2h

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