Question

A body is thrown from a point with speed 50 m/s at an angle 37⁰ with horizontal. When it has moved a horizontal distance of 80 m then it's distance from point of projection –

• A. 40 m
• B. 40 $\frac{2\pi r}{h}$m
• C. 40 $\sqrt{5}$ m
• D. None

Answer 1

Answer: (C)

40 $\sqrt{5}$ m

Answer 2

y = x tan q – $\frac { \mathrm { gx } ^ { 2 } } { 2 \mathrm { u } ^ { 2 } \cos ^ { 2 } \theta }$ then, r = $\sqrt { x ^ { 2 } + y ^ { 2 } }$