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Question

Question: A body is rolling without slipping on a horizontal surface and its rotational kinetic energy is equa...

A body is rolling without slipping on a horizontal surface and its rotational kinetic energy is equal to the translational kinetic energy. The body is:

A

Disc

B

Sphere

C

Cylinder

D

Ring

Answer

Ring

Explanation

Solution

12mv2(K2R2)=12mv2\frac { 1 } { 2 } m v ^ { 2 } \left( \frac { K ^ { 2 } } { R ^ { 2 } } \right) = \frac { 1 } { 2 } m v ^ { 2 }K2R2=1\frac { K ^ { 2 } } { R ^ { 2 } } = 1

i.e. the body is ring