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Question: A body is rolling down an inclined plant. If K.E. of rotation is 40% of K.E. in translatory state, t...

A body is rolling down an inclined plant. If K.E. of rotation is 40% of K.E. in translatory state, then the body is a:

A

Ring

B

Cylinder

C

Hollow ball

D

Solid ball

Answer

Solid ball

Explanation

Solution

12mv2(K2R2)=40%\frac { 1 } { 2 } m v ^ { 2 } \left( \frac { K ^ { 2 } } { R ^ { 2 } } \right) = 40 \% 12mv2\frac { 1 } { 2 } m v ^ { 2 }K2R2=40100\frac { K ^ { 2 } } { R ^ { 2 } } = \frac { 40 } { 100 } =25= \frac { 2 } { 5 } i.e. the body is solid circle