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Question

Physics Question on Motion in a straight line

A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second latter. Then the separation between two bodies, 2s2\,s after the release of the second body is, nearly

A

15 m

B

20 m

C

25 m

D

30 m

Answer

25 m

Explanation

Solution

s=ut+12at2s=u t+\frac{1}{2} a t^{2}
For 1st body u=0u =0 and a =g= g (freely falling body)
Distance covered in 2s2\, s
s1=0+12g(2)2s_{1}=0+\frac{1}{2} g(2)^{2}
For 2 nd body Distance covered in 2s2\, s
s2=0+12g(3)2s_{2}=0+\frac{1}{2} g(3)^{2}
hence s2s1=12g[(3)2(2)2]s_{2}-s_{1}=\frac{1}{2} g\left[(3)^{2}-(2)^{2}\right]
=12g[94]=\frac{1}{2} g[9-4]
=25m=25\, m