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Question: A body is projected with initial velocity \((2\widehat{i} + 2\widehat{j})\) m/s. The horizontal rang...

A body is projected with initial velocity (2i^+2j^)(2\widehat{i} + 2\widehat{j}) m/s. The horizontal range is approximately –

A

1 m

B

0.9 m

C

0.8 m

D

0.7 m

Answer

0.8 m

Explanation

Solution

u⃗=(2i^+2j^)\vec { u } = ( 2 \hat { i } + 2 \hat { j } ) m/s

R = 2uxuyg\frac { 2 u _ { x } u _ { y } } { g } = 2.2.2 g\frac { 2.2 .2 } { \mathrm {~g} } = 810\frac { 8 } { 10 } m = 0.8 m