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Question

Physics Question on Motion in a straight line

A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are t1t_1 and t2t_2, respectively. Then, the velocity of projection will be
(take g as acceleration due to gravity)

A

gt1t22\frac {g \sqrt {t_1t_2}}{2}

B

g(t1+t2)2\frac {g(t_1+t_2)}{2}

C

gt1t2g \sqrt {t_1t_2}

D

gt1t2(t1+t2)g \frac {t_1t_2}{(t_1+t_2)}

Answer

g(t1+t2)2\frac {g(t_1+t_2)}{2}

Explanation

Solution

The correct option is (B): g(t1+t2)2\frac {g(t_1+t_2)}{2}.