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Question

Physics Question on Gravitation

A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be:

A

800 km

B

1600 km

C

2133 km

D

4800 km

Answer

800 km

Explanation

Solution

**As per the theory of conservation of energy **

GMemRe+12m(132GmeRe))2=GMemRe+h-\frac{ GM_em }{ R_e} + \frac{1}{2}m\bigg(\frac{1}{3}\sqrt{\frac{2Gm_e}{R_e)}}\bigg)^2 = - \frac{GM_em}{R_e+h}

  • GMemRe+GMem9Re=GMemRe+h-\frac{GM_em}{R_e} + \frac{GM_em}{9R_e} = -\frac{GM_em}{R_e+h}

89Re=1Re+h\frac{8}{9R_e} = \frac{1}{R_e+h}

Therefore, the maximum height attained by the body will be:

h=Re8⇒ h = \frac{R_e}{8}

= 64008\frac{6400}{8}

= 800800 kmkm