Solveeit Logo

Question

Physics Question on Gravitation

A body is projected vertically upwards from the surface of a planet of radius RR with a velocity equal to half the escape velocity for that planet. The maximum height attained by the body is

A

R3\frac {R} {3}

B

R2\frac {R} {2}

C

R4\frac {R} {4}

D

R5\frac {R} {5}

Answer

R3\frac {R} {3}

Explanation

Solution

Total energy = K.E. + P.E. = 12m(122GMR)2+(GMmR)\frac{1}{2} m \left( \frac{1}{2} \sqrt{\frac{2GM}{R}}\right)^2 + (- \frac{GMm}{R})
= GMm4RGMmR=3GMm4R\frac{GMm}{4R} - \frac{GMm}{R} = - \frac{3GMm}{4R}
Final energy when body comes to rest at heigh
r=GMmRr = -\frac{GMm}{R} 3GMm4R=GMmr\therefore \frac{-3GMm}{4R} = \frac{GMm}{r} i.e. r=4R3r = \frac{4R}{3}
Max.height = r - R = 43\frac{4}{3} R - R = R3\frac{R}{3}