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Question: A body is projected horizontally from the top of a tower with initial velocity 18 ms<sup>–1</sup>. I...

A body is projected horizontally from the top of a tower with initial velocity 18 ms–1. It hits the ground at angle 45o. What is the vertical component of velocity when it strikes the ground

A

9 ms–1

B

92\sqrt{2}ms–1

C

18 ms–1

D

18 2\sqrt{2}ms–1

Answer

18 ms–1

Explanation

Solution

When the body strikes the ground

tan45o=vyvx=vy18\tan 45^{o} = \frac{v_{y}}{v_{x}} = \frac{v_{y}}{18}= 1

vy=18m/s.v_{y} = 18m/s.