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Question: A body is projected from the surface of earth with a velocity 2v<sub>e</sub> where v<sub>e</sub> is ...

A body is projected from the surface of earth with a velocity 2ve where ve is the escape velocity. The velocity of the body when it escapes the gravitational field of the earth is :

A

B

C

D

11ve\sqrt { 11 } \mathrm { v } _ { \mathrm { e } }

Answer

Explanation

Solution

v = n21\sqrt { \mathrm { n } ^ { 2 } - 1 } ve

or v = 221\sqrt { 2 ^ { 2 } - 1 } ve

v = 3\sqrt { 3 } ve